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How to convert this C array code to MIPS Assembly language?

Discussion in 'Assembly Language Programming (ALP) Forum' started by Jaebee, Feb 18, 2010.

  1. Jaebee

    Jaebee New Member

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    Hi all I'm working on a problem involving translating an example C array code into the MIPS version, but I'm not quite sure how to do it right. Here is the sample code:


    example: int count(int a[], int n, int x) {

    int res=0;
    int i;
    for(i=0;i!=n;i++)
    if(a==x)
    res=res+1;
    return res;
    }



    Here is what I have so far with my code according to what I understand. Any assistance would be appreciated!


    move $t0, $zero # register t0 = 0
    move $t1, $zero # register t1 = 0

    loop: sll $t2,$t0,2 #t2 = i * 4
    add $t3,$a0,$t2 # $t3 = address of array a[]
    sw $zero, 0($t2) # array a[] = 0

    bne $ # check the end of the loops
     
  2. virxen

    virxen New Member

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    here is a small example that i made for you.
    i do not use it as a function but as a single program.
    modify it to your needs.

    Code:
    .data
    str1: .asciiz "count="
    .align 2
    a: .space 5
    
    .text 
    .globl main
    
    main:
             #create the array
             la $9,a #load address  of the array
             addi $8,$0,5 #value to store
             sw $8,0($9) #store data in array a[0]=5
             addi $9,$9,4 #next element
             addi $8,$0,5 #value to store
             sw $8,0($9) #store data in array a[1]=5
             addi $9,$9,4 #next element
             addi $8,$0,5 #value to store
             sw $8,0($9) #store data in array a[2]=5
             addi $9,$9,4 #next element
             addi $8,$0,6 #value to store
             sw $8,0($9) #store data in array a[3]=6
             addi $9,$9,4 #next element
             addi $8,$0,7 #value to store
             sw $8,0($9) #store data in array a[4]=7
             addi $9,$9,4 #next element
            add $14,$0,$0 #res=0;
            addi $16,$0,10 #n=5;
            addi $17,$0,5 #x=5;
            add $18,$0,$0#i=0; in order to start loop from 0
            la $9,a #load address  of the array
            loop: #for 
            lw $15 ,0($9) #a[i]
            addi $9,$9,4 #next element
            bne $15,$17,notequal
            addi $14,$14,1 #res=res+1;
            notequal: 
            addi $18, $18, 1 # i=i+1;
            bne $18, $16, loop #next
            #print result
               addi $2,$0,4
               la $4,str1
               syscall #count=
               addi $2,$0,1
               add $4,$0,$14 
               syscall# res
    
    
    
    
     
  3. xyz

    xyz New Member

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    You can do the MIPS conversion using ctomips.com I used it to check against my homework. It works pretty well.
     

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