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If condition for moving to another page

Discussion in 'PHP' started by newphpcoder, Mar 10, 2011.

  1. newphpcoder

    newphpcoder New Member

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    Good day!
    I want to know what is wrong in my code that's why when i choose in select option it did not go to another page...Like when I select "Incoming" nothing happen also when I choose "Outgoing" nothing also happen.
    Here is my code:
    PHP:
    <?php
    include ("config.php");
    $call_type $_POST['call_type'];
    $query=mysql_query("SELECT `call_type` FROM `tbl_calltype` WHERE `call_type` = '{$call_type}'") or die(mysql_error());
    $result mysql_num_rows($query);
    if (
    $result == 1){
    if(
    $call_type == 'Incoming'){
     
    header ('Location:incoming.php');
    }
    elseif(
    $call_type == 'Outgoing'){
     
    header ('Location:outgoing.php');
    }
    else{
     
    header('Location:index.php');
    }
    }
    ?>
    <html>
    <body>
    <form id="form1" name="form1" method="post" action="">
      <select name="call_type">
        <option value="Select Call Type">Select Call Type</option>
        <option value="Incoming" <?php if($_POST['call_type'] == 'Incoming') echo "selected='selected'"?>>Incoming</option>
        <option value="Outgoing" <?php if($_POST['call_type'] == 'Outgoing') echo "selected='selected'"?>>Outgoing</option>
      </select>
    </form>
    </body>
    </html>
    Thank you
     
  2. shabbir

    shabbir Administrator Staff Member

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    On selecting the option you need to make the JS code to submit the page.
     
  3. newphpcoder

    newphpcoder New Member

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    I'm not familiar with js

    Thank you
     
  4. newphpcoder

    newphpcoder New Member

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    I tried this code:
    PHP:
    <?php
    include ("config.php");
    //ob_start();
    //header ('Location:incoming.php'); 
    if (isset($_POST['call_type'])) { // Check if form has been submitted
    $call_type mysql_real_escape_string($_POST['call_type']); // SECURE THE FECKING CONTENT!!!!!!!!!!!!!!!!!!!!!!
    echo $call_type;
    $query=mysql_query("SELECT `call_type` FROM `tbl_calltype` WHERE `call_type` = '{$call_type}'") or die(mysql_error());
    $result mysql_num_rows($query);
    echo 
    '<br />' $result;
    if (
    $result == 1){
    if(
    $call_type == 'Incoming'){
        
    header ('Location:incoming.php');
    }
    elseif(
    $call_type == 'Outgoing'){
        
    header ('Location:outgoing.php');
    }
    else{
        
    header('Location:index.php');
    }
    }
    }
    ?>
    <html>
     
    <body>
    <form id="form1" name="form1" method="post" action="">
      <select name="call_type">
        <option value="Select Call Type">Select Call Type</option>
        <option value="Incoming" <?php if($_POST['call_type'] == 'Incoming') echo "selected='selected'"?>>Incoming</option>
        <option value="Outgoing" <?php if($_POST['call_type'] == 'Outgoing') echo "selected='selected'"?>>Outgoing</option>
      </select>
      
      <input type="submit" name = "Submit" value="Submit">
    </form>
    </body>
    </html>
    And when I choose Incoming and I press submit button the output is:
    Incoming
    1
    Warning: Cannot modify header information - headers already sent by (output started at D:\xampp\htdocs\OJT\mae_ann\index.php:9) in D:\xampp\htdocs\OJT\mae_ann\index.php on line 17
    Thank you
     

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