in c++ you can do this
Code:
#include <iostream>
#include <conio.h>
int a(double sales,double sepcost){
double NRV;
NRV=sales-sepcost;
printf("The Net Realizable Value is: %.3lf\n",NRV);
}
int main()
{
double sales,sepcost;
char error[128];
do{
system("cls");
printf("Please input your Sales Value: \n");
std::cin>>sales;
if (std::cin.fail()){
std::cin.clear();
std::cin.ignore(std::numeric_limits<int>::max(),'\n');
sales=-1;
}
if(sales<0){
system("cls");
printf("Invalid input for Sales, Please try again!!\n");
system("pause");
}else{
printf("Please input your Separable Cost: \n");
std::cin>>sepcost;
if (std::cin.fail()){
std::cin.clear();
std::cin.ignore(std::numeric_limits<int>::max(),'\n');
sepcost=-1;
}
if(sepcost<0){
system("cls");
printf("Invalid input for Seperabe Cost, Please try again!!\n");
system("pause");
}
}
}while(sales<0||sepcost<0);
a(sales,sepcost);
getch();
}