



|
Banned
|
|
| 6Oct2009,09:21 | #1 |
|
how will you check the relation of two numbers (greater or lesser) without using Relational operators ??????
![]() ![]() ![]() ![]()
|
|
Newbie Member
|
|
| 6Oct2009,09:25 | #2 |
|
By comparing them using IF Else
|
|
Banned
|
|
| 6Oct2009,09:43 | #3 |
|
for comparing u need relational operator na
![]() ![]() , use if-else.. but the question is without relational operators how will u decide the relation between two numbers....? please
|
|
Ambitious contributor
|
![]() |
| 6Oct2009,11:33 | #4 |
|
You can do it using the following logic:
Let us assume the numbers to be x and y. Code:
if(x/y)
printf("x is greater");
else
printf("y is greater");
If you divide a smaller number by a greater number the result will be "zero". case 1: x<y (x/y) results "0", in turn makes the condition if(o) => if(false) and so the else part is executed. case 2:x>y (x/y) results some positive value, in turn makes the condition to if(true) and so if part is executed. |
|
Banned
|
|
| 6Oct2009,18:48 | #5 |
|
hmm.. it's correct
good...... but take the worst case , take 'x' and 'y' to be same......... so let us assume x=90 , y=90 , is 90>90 or 90<90 , this statement is false..... so in ur logic , the ur if() will be true for u....... actually it mustt be false.........and my question is for alll operators , and not only fot > & < , also for >= , <= and ==..... and i ll say a clue , in all relational operators only one thing will change entirely, by changing that u can write the logic and check it...... thank u |
|
Ambitious contributor
|
![]() |
| 8Oct2009,09:00 | #6 |
|
oh... Can you reveal the solution that you expected?
|
|
Banned
|
|
| 8Oct2009,23:55 | #7 |
|
just u try it sir..... it's simple.....
![]() ![]() ![]() ![]()
|
|
Ambitious contributor
|
![]() |
| 12Oct2009,16:08 | #8 |
|
If the two numbers are same, we can find that out using this XOR condition:
Code:
if(x^y)
printf("Both not equal");
else
printf("Both equal");
If x and y are equal, then condition becomes if(0). |
|
Banned
|
|
| 13Oct2009,07:50 | #9 |
|
HM-MM... for equality this is correct , for lesser or greater wat will be the logic....
|
|
Ambitious contributor
|
![]() |
| 13Oct2009,08:50 | #10 |
|
I have already posted the result for lesser or greater
|