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DaWei

Or, as mentioned in post #9,

Quote:

The name of the array is treated as a pointer to its first element. Since it's already a pointer, the address-of operator is not required.

If you're not reading your responses, why should we write them?

DaWei Team Leader
28Dec2006,22:06
	Or, as mentioned in post #9, Quote: The name of the array is treated as a pointer to its first element. Since it's already a pointer, the address-of operator is not required. If you're not reading your responses, why should we write them?