- a,b are both greater than 1
- a and b are not equal.
- a^2 + 3b and b^2 + 3a are perfect square.
Perfect Squares | 2 Oct 2009
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Go4Expert Founder
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| 2Oct2009,19:49 | #1 |
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Find a,b which satisfy the following
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Invasive contributor
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| 2Oct2009,20:30 | #2 |
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a = 11
b = 16 (or vice versa) 11 and 16 both are greater than 1 11 and 16 are not equal a^2 + 3b = 11^2 + 3*16 = 121+48 = 169 b^2 + 3a = 16^2 + 3*11 = 256+33 = 289 169 and 289 are perfect squares of 13 and 17 resp |
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Go4Expert Founder
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| 3Oct2009,11:00 | #3 |
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Bingo
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