Lets take the same structure x.

x needs 5 bytes (1 char + 1 integer) for its storage. Lets say x is stored from the address 1000 to 1004. As we know on a 32 bit machine, all memory word addressses are 4 multiples only ie, word addresses can be 1000, 1004,1008,1012....,2000,.... only. It cannot be either 1001 or 1002. Hence, when we access x.a(char), attempt on address 1000 is made by OS. Infact, OS actually reads 4 bytes(1000 1003) and extracts the first byte for the user. Thus, the char variable is accessed in single attempt. Consider the access of integer. It is stored in the region of 1001 to 1004. OS performs read on address 1000 first, extracts 3 bytes from it, then read address 1004, extracts one byte from it, do the necessary actions to formulate the integer, and finally return to user. Thus integer variable is accessed by 2 memory attempts alongwith few overhead operations for formulating the integer.

Am I answered your question correctly?

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